You can assign a value to one or more variables as shown below:
v = 5
print(v) # 5
v = 10
print(v) # 10*str type cannot be changed by accessing each character so use list() and join() to do that.
v = "Orange"
print(v, v[0], v[1], v[2], v[3], v[4], v[5]) # Orange O r a n g e
v = "Lemon"
print(v, v[0], v[1], v[2], v[3], v[4]) # Lemon L e m o n
v[2] = "M" # TypeError: 'str' object does not support item assignment
# ---------------------------------------------------------------------- #
v = "Lemon"
print(v, v[0], v[1], v[2], v[3], v[4]) # Lemon L e m o n
v = list(v) # Change `str` type to `list` type.
print(v, v[0], v[1], v[2], v[3], v[4]) # ['L', 'e', 'm', 'o', 'n'] L e m o n
v[2] = "M"
print(v, v[0], v[1], v[2], v[3], v[4]) # ['L', 'e', 'M', 'o', 'n'] L e M o n
v = ''.join(v) # Change `list` type to `str` type.
print(v, v[0], v[1], v[2], v[3], v[4]) # LeMon L e M o n# Equivalent
v1 = v2 = v3 = 5 # v1 = 5
# v2 = v1
# v3 = v2
print(v1, v2, v3) # 5, 5, 5
v2 = 10
print(v1, v2, v3) # 5, 10, 5*The reference of a list is stored in a variable so the variables v1, v2 and v3 have the same references of a list, that's why changing the list content of v2 also changes the other list content of v1 and v3.
# Equivalent
v1 = v2 = v3 = [0, 1, 2, 3, 4] # v1 = [0, 1, 2, 3, 4]
# v2 = v1
# v3 = v2
print(v1, v2, v3) # [0, 1, 2, 3, 4] [0, 1, 2, 3, 4] [0, 1, 2, 3, 4]
v2[2] = 20 # Changes the same list content by the same reference as v1 and v3.
print(v1, v2, v3) # [0, 1, 20, 3, 4] [0, 1, 20, 3, 4] [0, 1, 20, 3, 4]
v2 = list(v2) # v2 has the different reference of the different list
# from v1 and v3.
v2[2] = 200 # Changes a different list content by the different reference
# from v1 and v3.
print(v1, v2, v3) # [0, 1, 20, 3, 4] [0, 1, 200, 3, 4] [0, 1, 20, 3, 4]
v3 = 50 # Changes a list reference itself.
print(v1, v2, v3) # [0, 1, 20, 3, 4] [0, 1, 200, 3, 4] 50